Which of these will NOT create an integer variable in C++?

Prepare for the ASU CSE100 Programming Exam with C++ Study Guide. Review flashcards, multiple choice questions, with hints and explanations. Master your exam!

The choice that will not create an integer variable in C++ is the one that misplaces the keyword and the variable name. In the programming language C++, the declaration of a variable must follow specific syntax rules. The correct syntax for declaring an integer variable includes placing the type specifier (in this case, "int") before the variable name.

In the provided answer, the phrase "number int" mistakenly places the variable name before the type specifier, which is not valid in C++. The compiler will not recognize this as a valid statement and will throw a syntax error.

In contrast, the other options demonstrate proper syntax for variable declaration. The first option simply declares an integer variable named "number." The third option also declares an integer variable and initializes it with a value of 10. The fourth option uses a different initialization method, known as direct initialization, to assign the value of 100 to the variable "number." Each of these adheres to the correct format required in C++.

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