What will the following code: int x = 10; x++; return x; return 5; yield?

The code snippet provided demonstrates how the increment operator and the return statement operate in sequence. Initially, the variable x is assigned the value of 10. The subsequent statement x++ uses the post-increment operator, which increases the value of x by 1 after its current value is evaluated. Since x is initially 10, after the x++ operation, x becomes 11.

The first return statement, return x;, will return the current value of x, which is now 11. After a return statement is reached, control exits from the function, so any code placed after the first return statement will not be executed. As a result, the second return statement, return 5;, would never be executed. Thus, the function effectively ends after returning the incremented value.

Therefore, when the function with this code is invoked, it will yield the value 11, confirming that the correct answer is the third choice.