What is the outcome of using 'myFile.open("filename.txt");' in C++?

Using 'myFile.open("filename.txt");' in C++ is primarily to open the specified file for reading or writing, depending on the mode set (which is not specified in this case). In its default state, if no specific mode is defined, the open function typically assumes an intention to read from the file. Therefore, when you call this method, the expected outcome is that the file will be opened for reading if it exists.

If the file "filename.txt" exists in the directory, the program will gain access to that file for reading its contents. If the file does not exist, the operation may fail, but it does not delete the file or copy it. The default mode tends to be to open the file in a way that allows for data to be read but does not modify it unless explicitly specified.

Understanding file operations in C++ is crucial for handling data correctly, and this method provides a foundational way to interact with files in your programs.