How do you correctly define a member function outside of a class in C++?

To correctly define a member function outside of a class in C++, the proper syntax requires using the scope resolution operator :: to associate the function definition with the specific class it belongs to. This means that the function definition starts with the return type, followed by the class name and the scope resolution operator, leading into the function name and its parameters within parentheses.

This method enables the compiler to understand that the function being defined is not a standalone function, but rather a member of the specified class. This is essential for properly organizing code in object-oriented programming and ensuring that the function has access to the members and methods of the class.

The other options lack correct structure as follows: one incorrectly places the function name before the class name, another uses a dot notation instead of the scope resolution operator, and one misplaced the return type and class name, which does not conform to C++ syntax.